Question

A block weight 100n is pushed by a force F on horizontal rough plane moving with acceleration 1m/s ehen force is doubled acceleration becomes 10 then coefficient of friction is

Answer 1

Take g = 10m/s^2

Final Answer : $\mu = 0.8$

Steps:
1) Weight = 100 N
=> mg = 100N
=> m = 10 Kg

Let the External Force be F and friction force be f.
Then, according to the Question :
Normal ,N= W = 100 N
$F - f = ma \\ => F - \mu N = ma \\ => F - 100 \mu = 10*1 --(1)$

2) We know, When Force is doubled, a becomes 10 units.
$2F - 100 \mu = ma \\ => 2 F - 100 \mu = 10*10 \\ => 2 F - 100 \mu = 100 ---(2)$

3) Solving above equations we get,
$\mu =0.8$

Hence, Coefficient of friction is 0.8 .

Answer 2

Answer:

the co efficient of friction found is 0.8