Physics, asked by wajadahmed211, 6 months ago

A block which has a mass of 2 kg is attached to a spring and placed on a horizontal
frictionless table. The spring is stretched 40 cm when a force of 10 N is applied.
Calculate the spring constant.​

Answers

Answered by Anonymous
2

A mass of 2kg is attached to thespring of spring constant `50Nm^(-1)`. The block is pulled to a. A mass of 2kg is attached to thespring of spring constant `50Nm^(-1)`. The block is pulled to a distance of 5 cm from its equilibrium position at `x=0` on a horizontal frictionless surface from rest at t=0.

Here, m=2kg,k=50Nm−1,A=5cm=0.05m.

The block exectues SHM.

Its angular frequency is given by

ω=mk=2kg50Nm−1=5rads−1.

Since the time is noted from the equilibrium position,

its displacement at any time t is given by

x=Asinωt=0.05sin5tm

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