Question

A block whose is 1kg is fastened to a Spring .the spring has a spring, constant of 50 N/m, what is its angular velocity.​

Answer 1

Answer:

7.07 rad/s or 5√2 rad/s

Explanation:

Analyzing the question,

Given:

• Mass = 1 kg
• Spring constant = 50 N/m

To find:

• Angular velocity = ?

Solution:

For solving this question, we apply this formula:

k = ω² m

where:

• k is the spring constant
• ω is the angular velocity
• m is the mass of the block

Substituting the given values in the formula,

➝ 50 = ω² × 1

➝ ω² = 50

➝ ω = √50

➝ ω = 7.07 rad/s

∴ The angular velocity = 7.07 rad/s

Answer 2

Answer:-

• Mass=m=1kg
• Spring constant=50N/m
• Angular velocity=?

We know that

$\boxed{\sf \omega^2=\dfrac{k}{m}}$

$\\ \sf\longmapsto \omega^2=\dfrac{50}{1}$

$\\ \sf\longmapsto \omega^2=50$

$\\ \sf\longmapsto \omega=\sqrt{50}$

$\\ \sf\longmapsto \omega=5\sqrt{2}rad/s$

$\\ \underline{\boxed{\bf{\therefore \omega=5\sqrt{2}rad/s}}}$