Question

A block whose mass is 1kg is fastened to a spring. The spring has a spring constant of 100Nm
−1
. The block is pulled to a distance x=10cm from its equilibrium position at x=0 on a frictionless surface from rest at t=0. The kinetic energy and potential energy of the block when it is 5cm away from the mean position is ​

Answer 1

Answer:

0.125j

Explanation:

Mass=1kg

Spring constant=10N/m

x=10cm

x=0

t=0

Kinetic energy and potential energy of the block=5cm away from the mean position

Angular frequencyω=

k/m

ω=

50/1

=7.07rad/s

Its displacement at any time t is then given byx(t)=0.1cos(7.07t)

P.E=

2

1

kx

2

=

2

1

×100×(0.1)

2

=

2

1

×100×

1000

1

=0.125J