Question

A block X of mass “m” strikes another block Y of mass “2m”. Both the blocks
collide and at point of collision the block X exerts the force of 10 N to block
Y. What will be the magnitude and direction of the force exerted by block Y?
(a)10 N, in the same direction of force of block X
(b)20 N, in the same direction of force of block X
(c)10 N, opposite to the direction of force of block X
(d)20 N, opposite to the direction of force of block X

Answer 1

Answer:

20N ,in the same direction of force of X

Answer 2

The Main Answer is: (c) 10N. opposite to the direction of the force of block X

Given: Block X - mass = m

           Block Y - mass = 2m

           They collide and X exerts a force of 10N on Y

To Find: The magnitude and direction of the force exerted by block Y

Solution:

This question uses the concept of "Newton's Third Law of Motion".

• Newton's third law of motion states that "Every action has an equal and opposite reaction".
• Using this law, we can conclude that, in this question, the force exerted by both the blocks on each other will be equal in magnitude but opposite in direction.
• Therefore, as block X exerts a force of 10N on block Y, we can say that block Y also exerts a force of 10N on block X but in the opposite direction, despite the difference in their masses.

A common mistake that can be made is to mark the force exerted by block Y as 20N due to it having mass = 2m.

This is not correct because in such a case, in accordance with the formula F = ma, due to different masses, the acceleration acquired by both the blocks will be different to keep the magnitude of forces equal.

Hence, the force exerted by block Y is 10N in opposite direction to the force applied by block X.

For a similar question on collision, refer to:

https://brainly.in/question/5391336?msp_srt_exp=6

For more information on Newton's Third Law, refer to:

https://brainly.in/question/25783451?msp_srt_exp=6

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