A blockof mass 20 kg is moved along an inclained plane inclination 37°
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From equilibrium of forces along the incline,
mgsin\theta+\mu mg cos\theta=F
\implies F=160N
Power=Fv=constant=50W
\implies v=\dfrac{5}{16}m/s
Power used against gravity=\vec{F_g}
.\vec{v}=-mgsin\theta v=37.5W
Hence fraction of power used=75%
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