A blocks of mass m is pulled on a rough horizontal surface which has a friction coefficient mew. A horizontal for F is applied which is capable of moving the body uniformly with speed v. Find the work done on the block in time
t by (a) weight of the block, (b) Normal reaction by surface on the block, (c) friction, (d) F.
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similarly find the last.
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depanshusingla2:
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ANSWER
a) W=mg
but here mg makes an angle of 90 with the force (since force is horizontal)
therfore work=0
b) here Normall=mg
which is also at an angle of 90 from force therefore work done by normal=0
c) here lets take the force of friction as f
so f=μN
and N=-mg
therefor f=-umg
and here distance= velocity X time
=vt
therefore
w=-umgt
d) here F=-f
since force=- of friction
so
F=umg
therefore
w=umgvt
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