a Blok of mass m is suspended by a light thread from an elevator. the elevator is accelerating upward with uniform acceleration a work done during t s by the tension in the thread is
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This can be obtained in two ways:
Pseudo force on the mass downwards = ma
As the mass is in static equilibrium inside the lift, the value of tension T in the string = mg + ma = m(g+a)
Distance moved by the lift in time t sec. = h = 1/2 a t²
So work done = force * distance = 1/2 * m a (g+a) t²
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Kinetic energy of the mass = 1/2 m v² = 1/2 * m (a t)²
Potential energy of the mass at time t = m g h = m g (1/2 a t²)
Total energy (increase) of the mass = 1/2 * m a t² (a + g)
Pseudo force on the mass downwards = ma
As the mass is in static equilibrium inside the lift, the value of tension T in the string = mg + ma = m(g+a)
Distance moved by the lift in time t sec. = h = 1/2 a t²
So work done = force * distance = 1/2 * m a (g+a) t²
=============
Kinetic energy of the mass = 1/2 m v² = 1/2 * m (a t)²
Potential energy of the mass at time t = m g h = m g (1/2 a t²)
Total energy (increase) of the mass = 1/2 * m a t² (a + g)
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