Question

A blok slides down a rough inclined plane of inclination 45' . if coefficient of kinetic friction is 0.5, find the acceleration of the sliding block

Answer 1

$a = \: net \: force \div mass$
net force = mgsin(theta) - umgcos(theta)

$a \: = g(\sin(theta) - u \cos(theta) )$
a= 10(1/√2 - 1/2 × 1/√2 )
a= 10 1/√2 (1-1/2)
a=10 ×1/√2(1/2)
a= 5/√2