Question

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a blue eyed man was married with a Brown eyed lady. They produced 6 child and all of child by blue eyed.Then represent the cross and the chequerboard and find genotypes and phenotypes of this family.

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Answer 1

Answer:

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Explanation:

(a) Since the mother is blue-eyed, her genotype will be bb (recessive trait). While the son is brown eyed, therefore, his genotype will be Bb (heterozygous).

(b) Since the son is brown eyed means father will also be brown eyed. So, the possible genotypes will be BB or Bb.

(c) Man is brown eyed, will have genotype Bb. The woman is blue-eyed will have genotypes bb. Thus the possible genotypes of their offsprings will be:

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