Question

.A BMW car travelling at 22.4 m/s skids to a stop in 2.55 s. Determine the skidding distance of the car (assume uniform acceleration

Answer 1

Answer:

the skidding distance of the car is 1 cm

Answer 2

Answer:

Explanation:

initial velocity = 22.4

time = 2.55 s

final velocity = 0

by equations of motion we know that: v = u+at

therefore: 0= 22.4 + a*2.55

= a = 8.74

therefore as: v^2 - u^2 = 2as

= s = 28.56