A boat at anchor is rocked by waves whose crests are 100 m apart and whose velocity is 25
m/sec. These waves strike the boat once every
(A) 2500 sec
(B) 0.25 sec
(C) 1500 sec
(D) 4 sec
Answers
Answered by
5
Answer:
Correct option is
C
4s
The distance between the two consecutive crests in transverse wave motion is called wavelength.
The boat bounces up, ie, it travels from crest to the consecutive crest along wave motion.
Wavelength =distance between two consecutive crests
ie,
Velocity of wave =2m/s
Hence, time in one bounce of boat
t=
v
λ
=
25
100
=4s
Explanation:
hope it's helps
Answered by
0
Answer:
We use a basic formula from 'Waves.'
velocity= frequency*wavelength
v= 25 m/s, wavelength= distance between 2 crests or 2 troughs= 100m
Frequency= 25/100= 1/4 Hz
Time period= 1/ frequency= 4s (D)
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