Question

a boat covers a distance of 12 km in 30 minutes towards the flow of water. If the speed of the boat in stagnant water is one-fourth (1/4) of the speed of the boat in flowing water, then how much distance will the boat cover in 20 minutes in stagnant water?​

Answer 1

Answer:

The distance covered by the boat is 2 km

Step-by-step explanation:

Let the speed of the boat in stagnant water is v and the speed of the flow of water is u

Then the speed of the boat in the flow of water will be = v + u

Given that

v = (1/4)(v + u)

or, 4v = v + u

or u = 3v

Therefore, speed of the boat in the flow of water = v + 3v = 4v

Since the boat covers 12 km in 30 minutes

Therefore,

using distance = speed × time

12 = 4v × 30

or, v = 1/10 km/min

Thus, the speed of the boat in stagnant water is 1/10 km/min

Distance covered in stagnant water in 20 minutes

= (1/10) × 20

= 2 km

Hope this is helpful.