Physics, asked by murshida, 1 year ago

a boat covers certain distance between two spots in a river taking t1 hrs going downstream and t2 hrs going upstream .What time will be taken by boat to cover same distance in still water?

Answers

Answered by sanjana44
245
Let velocity of water be u and velocity of boat in still water be v
Let distance traveled be d
We need to find d/v
t1= d/(v+u)
d= t1 v + t1 u (1)
t2= d/(v-u)
d = t2 v- t2 u (2)
From 1&2
v t1 + u t1= v t2- u t2
u(t1+ t2) = v(t2- t1)
u = v(t2-t1) / (t1+t2)
Substituting value of u in (1)
d = t1v + t1 [v(t2-t1) /t1+t2)]
d(t1+t2) = t1v(t1+t2) + vt1 (t2-t1)
d(t1+t2) = t1vt1 + t2t1v + vt1t2 - t1t1v
d(t1+t2) =2vt1t2
d/v = 2t1t2/( t1+t2)
Here d/v represents time taken by boat to cover a distance of d in still water
Answered by VIBEKTIGGA
0

Answer:

2t1t2/(t1+t2)

Explanation:

  • Let velocity of water be u and velocity of boat in

  • still water be v

  • Let distance traveled be d

  • We need to find d/v

  • t1= d/(v+u)

  • d= t1 v + t1 u (1)

  • t2=d/(v-u)

  • d = t2 v- t2 u (2)

  • From 1&2 v t1+ u t1= v t2- u t2

  • u(t1+ t2) = v(t2-t1)

  • u = v(t2-t1) / (t1+t2) Substituting value of u in (1)

  • d = t1v+t1 [v(t2-t1) /t1+t2)] d(t1+t2) = t1v(t1+t2) + vt1 (t2-t1)

  • d(t1+t2) = t1vt1 + t2t1v + vt1t2 - t1t1v

  • d(t1+t2) =2vt1t2

  • d/v = 2t1t2/(t1+t2)

Here d/v represents time taken by boat to cover a distance of d in still water

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