Math, asked by anubhavgg0099, 3 days ago

A boat first travels 48 km downstream and 24 km upstream in 7 hours. Then it travels for 9 hours, going 48 km upstream and 36 km downstream. Find the speed of the boat in still water and the speed of the water current. ​

Answers

Answered by azamzaid2007
0

Answer:

Good Question , Your answer is here.

Let the Speed of the Water Current be x km/hr.

→In Case of the Downstream,←

Distance Covered by the Boat in Downstream = 36 km.

       

  Speed of the Boat in Downstream = (12 + x) km/hr.

Using the Formula,

         → Speed = Distance/Time

         → Time(T1) =  36/(12 = x) hrs.

→In case of Upstream,←

 Distance covered by the Boat in Upstream = 36 km.

          Speed of the Boat in Upstream = ( 12 - x) km/hr.  

        Thus, Time(T2) = 36/(12 - x) hrs.

⇒According to the Question,

                    T1  + T2 = 8 hrs.

           

           36/(12 + x) + 36/(12 - x) = 8

           

      36[ 12 - x + 12 + x] = 8(12 - x)(12 + x)

                        36 × 24 = 8 [144 - x²]

                    ⇒   108 = 144 - x²

                            x² = 144 - 108

                            x² = 36

                            x = √36

                     x = +6   or    x = -6

Since x = -6 cannot be possible because speed of the current cannot be negative.

⇔Thus, Speed of the Water Current is 6 km/hr.⇔

Step-by-step explanation:

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