A boat goes 12 km upstream and 40 km downstream in 8 hours. It can go 16 km upstream and 32 km downstream is the same time. Find the speed of the boat in still water and the speed of the stream.
Answers
Answered by
583
let speed of boat is x and stream is y
speed of boat upstream = x-y
speed of boat downstream = x+y
8 = 12/(x-y) + 40/(x+y)
8(x²-y²) = 52x -28y ..................(1)
8 = 16/(x-y) + 32/(x+y)
8(x²-y²) = 48x - 16y ..................(2)
(1) - (2)
4x - 12y = 0
x = 3y .........................(3) put in equation (1)
8(9y²-y²) = 52*3y - 28y
64y² = 128y
y = 0 or 2
y= 0 not possible
put y = 2 in equation (3)
x = 6Km./h (speed of boat in still water)
y = 2Km./h (speed of stream)
speed of boat upstream = x-y
speed of boat downstream = x+y
8 = 12/(x-y) + 40/(x+y)
8(x²-y²) = 52x -28y ..................(1)
8 = 16/(x-y) + 32/(x+y)
8(x²-y²) = 48x - 16y ..................(2)
(1) - (2)
4x - 12y = 0
x = 3y .........................(3) put in equation (1)
8(9y²-y²) = 52*3y - 28y
64y² = 128y
y = 0 or 2
y= 0 not possible
put y = 2 in equation (3)
x = 6Km./h (speed of boat in still water)
y = 2Km./h (speed of stream)
Answered by
151
let speed of boat be x and speed of stream be y
speed of boat upstream = x-y
speed of boat downstream = x+y
12/(x-y) + 40/(x+y) = 8
8(x²-y²) = 52x -28y ..................(1) [LCM (x-y)(x+y)]
16/(x-y) + 32/(x+y) =8
8(x²-y²) = 48x - 16y ..................(2) [LCM (x-y)(x+y)]
subtracting eq (1) - (2) we get
8(x²-y²) = 52x -28y
8(x²-y²) = 48x -16y
____________________
0 = 4x -12y
x = 3y .........................(3) put in equation (1)
8(9y²-y²) = 52*3y - 28y
64y² = 128y
y = 0 or 2
y= 0 not possible
put y = 2 in equation (3)
x = 6Km./h (speed of boat in still water) ANS
y = 2Km./h (speed of stream) ANS
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