A boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hour it can go 40 km upstream and 55 km downstream. If speed of the boat in still water is x km/hr and speed of stream be y km/hr, then - (1) x = 8 (2) y = 4 (3) x = 3 (4) y = 8
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Hey
Here is your answer,
Let the speed of the stream be = u kmph
let the speed of the boat be = v kmph
speed upstream will be = v - u kmph
speed downstream will be = v + u kmph
30 km upstream in time duration = 30 / (v - u) hrs
44 km down stream in time duration = 44 / (v + u) hrs
44 / (v + u) + 30 / (v -u) = 10 hrs --- (1)
Similarly,
40 /(v - u) + 55 / (v +u) = 13 hrs Multiply with 3/4:
30/(v-u) + 165 / 4(v+u) = 39/4 --- (2)
Now (1) - (2) => [44 - 165/4] / (v+u) = 10 - 39/4 = 1/4
=> v + u = 11 --- (3)
Substitute this in (1) to get:
44/11 + 30/(v-u) = 10
=> v - u = 30/6 = 5 --- (4)
Solving (3) and (4) , we get : v = 8 kmph and u = 3 kmph
The correct options are (3) and (4).
Hope it helps you!
Mark brainliest plz...
Here is your answer,
Let the speed of the stream be = u kmph
let the speed of the boat be = v kmph
speed upstream will be = v - u kmph
speed downstream will be = v + u kmph
30 km upstream in time duration = 30 / (v - u) hrs
44 km down stream in time duration = 44 / (v + u) hrs
44 / (v + u) + 30 / (v -u) = 10 hrs --- (1)
Similarly,
40 /(v - u) + 55 / (v +u) = 13 hrs Multiply with 3/4:
30/(v-u) + 165 / 4(v+u) = 39/4 --- (2)
Now (1) - (2) => [44 - 165/4] / (v+u) = 10 - 39/4 = 1/4
=> v + u = 11 --- (3)
Substitute this in (1) to get:
44/11 + 30/(v-u) = 10
=> v - u = 30/6 = 5 --- (4)
Solving (3) and (4) , we get : v = 8 kmph and u = 3 kmph
The correct options are (3) and (4).
Hope it helps you!
Mark brainliest plz...
adityajune02:
Thnx it was very helpful to me
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