Physics, asked by Ananyasingh7468, 1 year ago

A boat goes 30 km upstream and 44 km downstream in 10 hours . In 13 hours , it can go 40 km upstream and 55 km down-steam . Determine the speed of the stream and that of the boat in still water .

Answers

Answered by omegads04
2

Given

In 10 hours the boat covers a distance of 30 km upstream and 44 km downstream. ------(1)

And in 13 hours the boat covers a distance of 40 km upstream and 55 km downstream. ------(2)

Now let the speed of boat in still water = x km/h

and let the speed of stream = y km/h

Thus downstream speed = x+y and

upstream speed = x- y

We know

Speed = Distance/ Time

Time = Distance/ Speed.

For condition 1 we have

(Upstream distance/ speed upstream) +(downstream distance/ speed downstream) = 10 hour

(30/x-y)+(44/x+y) = 10 -----(A)

For condition 2

(40/x-y) + (55/x+y) = 13 -----(B)

considering (1/x-y) = a and (1/x+y) = b -------(3)

Thus A and B can be written as,

30 a + 44 b = 10 -----(C)

40 a + 55 b = 13 -----(D)

Subtracting C and D we get

C × 4 ----> 120 a +176 b = 40

D × 3 ----> 120 a + 165 b =39

b = 1/11 -----(E)

Putting E in C we get,

30 a + 44(1/11) = 10

a = 6/30 = 1/5

Reducing the above found values in 3 we get,

(1/x - y) = 1/5                   (1/x+y) =1/11

x -y = 5                            x + y = 11                  

x = 5+ y                           5 + y + y =11

x = 5+ 3                           y = 6/2 = 3 km/h    

x = 8 km/h

Answered by BendingReality
0

Answer:

Speed of stream = 3 km / hr.

Speed of boat in still water = 8 km / hr.

Step-by-step explanation:

Let the speed of the boat in still water be a km / hr and stream be b km / hr

For upstream = a - b

For downstream = a + b

We know :

Speed = Distance / Time

Case 1 .

10 = 30 / a - b + 44 / a + b

Let 1 / a - b = x and 1 / a + b = y

30 x + 44 y = 10 ... ( i )

Case 2 .

13 = 40 / a - b + 55 / a + b

40 x + 55 y = 13 ... ( i )

Multiply by 4 in ( i ) and by 3 in ( ii )

120 x + 176 y = 40

120 x = 40 - 176 y ... ( iii )

120 x + 165 y = 39

120 = 39 - 165 y ... ( iv )

From ( iii )  and  ( iv )

40 - 176 y = 39 - 165 y

11 y = 1

y = 1 / 11

120 x = 40 - 176 y

120 x = 40 - 176 / 11

x = 1 / 5

Now :

1 / a - b = 1 / 5

a - b = 5

a = 5 + b ... ( v )

1 / a + b = 1 / 11

a + b = 11

a = 11 - b ... ( vi )  

From ( v  ) and ( vi )

11 - b = 5  + b

2 b = 6

b = 3

a = 5 + b

a = 5 + 3

a = 8

Hence we get answer.

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