A boat goes 30km upstream and 20 km downstream in 7 hours.in 6 hours it can go 18km upstream and 30 km downstream.determine the speed of the stream and that of the boat in still water
Answers
let the speed of stream be y km/h
speed of upstream=X-Y
speed of downstream=X+Y
A.T.Q,
30/X-Y + 20/X+Y = 7
18/X-Y + 30/X+Y = 6
Let 1/X-Y be a and 1/X+Y be b
So, 30a + 20b = 7 -1
18a + 30b =6 -2
Mutiplying 1 by 3 and 2 by 5
so , 90a + 60b = 21
90a + 150b = 30
so , b= 1/10 =1/X+Y
a = 1/6 = 1/X-Y
SO X+Y = 10
X-Y = 6
SO X=8 km/h
Y=2 km/h
Given:
The upstream distance in 7 hours = 30km
The downstream distance in 7 hours = 20km
The upstream distance in 6 hours = 18km
The downstream distance in 6 hours = 30km
To find:
The speed of the stream and that of the boat in still water
Solution:
Let the speed of the boat in still water be x km per hour. and the speed of the stream be y km per hour.
We know that during the upstream journey, the velocity of the boat is x-y and during the downstream journey the velocity is x+y.
Case I :
The boat goes 30 km upstream and 20 km downstream in 7 hours.
Since, Time = distance/speed
⇒
Similarly,
Case II:
In 6 hours, it can go 18 km upstream and 30 km downstream.
⇒
Let us assume that 1/(x - y) = M
1/(x + y) = N
Substituting in the above equations,
30M + 20N = 7
or M = (7 - 20N)/30 - (1)
Also, 18M + 30N = 6 - (2)
Solving equations 1 and 2,
18[(7 - 20N)/30] + 30N = 6
⇒ (126 - 360N)/30 + 30N = 6
or 126 - 360N + 900N = 180
or N = 54/540
= 1/10
Substituting the value of N in equation (1) we get :
M = (7 - 20 × 1/10)/30
or M = (7 - 2)/30 = 5/30
= 1/6
Now, M = 1/(x - y) = 1/6
⇒ x - y = 6 - (3)
Also, N = 1/(x + y) = 1/10
or x + y = 10 -(4)
Solving equations (3) and (4) we get,
y = 2
Substituting the value of y in equation 3
x = 6 + 2
or x= 8