a boat goes 30km upstream and 44km down stream in 10 hours. In 13 hours it can go 40km upstream and 55km downstream. Determine the speed of the stream and that of the boat in still water
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we know that upstream (x-y)
downstream (x+y)
ATQ
30/(x-y)+44/(x+y)= 10---- eq 1
40/(x-y)+55(x+y)= 13----eq2
let (x-y)= U
let (x+y)= V
30u+44v=10
40u+55v=13
by elimination
120u+1760v=400
120u+1650v=390
110v=10
v = 1/11
put v in eq
30u+44*1/11=10
30u=10-4
30u=6
u=1/5
Now
U = x-y= 5
V = X+Y=11
2y= 6
y= 3
x=8
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