A boat goes 9 km an hour in still water. But it takes thrice as much time in going the s ame distance against the current. What is the speed of the current?
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Say the velocity of the boat be X km/h and velocity of the current be y km/h.
It goes x=9 km/h in still water.
then when the boat goes against the current, its velocity is (x-y)=(9-y)km/h
For distance s, time taken in still water to cover the distance = S/9 seconds.
For same distance s, time taken while going against the current = S/(9-y) seconds
so the equation will be, S/(9-y) = 3 X (S/9)
=>1/(9-y)=1/3
=>9-y=3
=>y=6
So, the speed of the current is 6 km/h.
It goes x=9 km/h in still water.
then when the boat goes against the current, its velocity is (x-y)=(9-y)km/h
For distance s, time taken in still water to cover the distance = S/9 seconds.
For same distance s, time taken while going against the current = S/(9-y) seconds
so the equation will be, S/(9-y) = 3 X (S/9)
=>1/(9-y)=1/3
=>9-y=3
=>y=6
So, the speed of the current is 6 km/h.
rajanc:
Thanks for the quick and great answer.
most welcome
Answered by
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Given :
- A boat goes 9 km an hour in still water. But it takes thrice as much time in going the s ame distance against the current.
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Find :
- What is the speed of the current?
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Using formula :
★ Speed of current = (Speed of boat - x) = Distance agaist the current.
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Calculations :
- As per this concept, let us assume "x" as the speed of the current.
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→ Speed of current = 1/(9 - x) = 1/3
→ Speed of current = 9 - x = 3
→ Speed of current = x = 9 - 3
→ Speed of current = x = 6 km/hr
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Therefore, 6 km/hr is the speed of the current.
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