Question

 A boat is rocked by waves such that a crest and a trough reach an interval of 0.1sec with a speed of 50 m/s. The distance between two consecutive crests is​

Answer 1

The distance between two consecutive crests us 5 m.

Explanation:

It is given that,

A boat is rocked by waves such that a crest and a trough reach an interval of 0.1 sec with a speed of 50 m/s.

We need to find the distance between two consecutive crest. It means its wavelength.

Frequency of wave is,

$f=\dfrac{1}{T}=\dfrac{1}{0.1}=10\ Hz$

Wavelength of a wave is :

$\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{50}{10}\\\\\lambda=5\ m$

So, the distance between two consecutive crests us 5 m.

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Answer 2

Given that,

Speed = 50 m/s

Time = 0.1 sec

Wave length :

The distance between two consecutive crests is​ called wavelength.

Wave length is equal to the velocity divided by frequency.

In mathematically form,

$\lambda=\dfrac{v}{f}$

We need to calculate the distance between two consecutive crests

Using formula of wavelength

$\lambda=\dfrac{v}{f}$

$\lambda=vt$

Here, $f = \dfrac{1}{t}$

Put the value into the formula

$\lambda=50\times0.1$

$\lambda=5\ m$

Hence, ​The distance between two consecutive crests is 5 m.