A boat is sent across a river with a velocity of 8km/hr. If the resultant velocity of the boat is 10km/hr, then the velocity of the river is
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howdy!!
your answer is----
let the velocity of river is Vr.
Given, velocity of boat Vb = 8km/h
and resultant velocity VR = 10km/h
since, angle between Vb and Vr is 90°
so , | Vr + Vb | = VR
==> √ 8^2 + Vr^2 + 2 VrVb cos ∅ = 10
==> √ 64+Vr^2 + 2 VrVb cos 90° = 10
==> 64 + Vr^2 = 100
==> Vr^2 = 100-64 = 36
==> Vr = √36 = 6km/h
hence, the velocity of river is 6km/h
hope it help you
your answer is----
let the velocity of river is Vr.
Given, velocity of boat Vb = 8km/h
and resultant velocity VR = 10km/h
since, angle between Vb and Vr is 90°
so , | Vr + Vb | = VR
==> √ 8^2 + Vr^2 + 2 VrVb cos ∅ = 10
==> √ 64+Vr^2 + 2 VrVb cos 90° = 10
==> 64 + Vr^2 = 100
==> Vr^2 = 100-64 = 36
==> Vr = √36 = 6km/h
hence, the velocity of river is 6km/h
hope it help you
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