Question

A boat is stationary at 11 meters away from the dock and begins to move toward the dock with an acceleration of 5.0 m/s2 How long will it take the boat to reach the dock?

Answer 1

Answer:

Using,

S = ut + 1/2at×t

11=0 + 2.5t^2

11/2.5 = t^2

4.4 = t^2

t = √4.4

Answer 2

Answer:

The boat will take 2.097 seconds to reach the dock.

Explanation:

The relationship between acceleration, displacement and velocity represented as a function of time are given by three equations of motion in physics.

• $v= u+ at$
• $s=ut+ 1/2at^{2}$
• $v^{2} = u^{2} + 2as$

where, s= displacement , u= initial velocity, v= final velocity, a= acceleration, t= time

We can use any of the equations, to find displacement, acceleration, time, final and initial velocity.

Calculation:

We are given displacement = 11m , acceleration=  5$m/s^{2}$.

As, we know that the boat is stationary so initial velocity (u) will be 0 m/s.

Now, to calculate time we use 2nd equation of motion as:

• $11 = (0)*t + \frac{1}{2}* 5 * t^{2}$
• $11 = \frac{1}{2}* 5 * t^{2}$
• $\frac{22}{5}= t^{2}$
• $4.4 = t^{2}$
• $t=2.097 sec$

To follow similar questions and concepts refer: https://brainly.in/question/17181781