Question

A boat man rowed to a place along the current and returned against the current in 15hrs. If the speed of the boat in still water is 6km/h and that of the current be 2km/h then find the distance of the place.​

Answer 1

I do not know answer

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Answer 2

$\large\underline\mathrm\red{Given:-}$

• $\large\mathrm{Total \: time \: taken \: = \: 15 \: hr}$

• $\large\mathrm{Speed \: of \: boat \: = \: 6 \: km/hr}$

• $\large\mathrm{Speed \: of \: current \: = \: 2 \: km/hr}$

$\large\underline\mathrm\red{To \: find}$

• $\large\mathrm{Distance \: of \: the \: place?}$

$\large\underline\mathrm\red{Solution}$

✰ $\large\mathrm{Let \: the \: distance \: be \: x}$

$\large\mathrm{The \: time \: taken \: while \: going \: to \: place \: be \: t.}$

$\large\mathrm{≫ \: Speed \: against \: current \: ( 6 \: - \: 2 )km/hr}$

$\large\mathrm{⟹ 4 \: km/hr}$

$\large\mathrm{≫ \: Speed \: along \: current \: = \: ( 6 \: + \: 2 ) \: km/hr}$

$\large\mathrm{⟹ 8 \: km/hr}$

$\large\mathrm{⟹ Sailed \: along \: with \: current \: while \: going.}$

$\large\underline\mathrm\red{Distance \: ⟹ \: speed \: × \: time}$

$\large\mathrm{⟹ x \: = \: 8 \: × \: t}$

$\large\mathrm{⟹ x = 8t}$_____(1)

$\large\mathrm{⟹ Sailed \: against \: current \: while \: returning.}$

$\large\mathrm{⟹ x = 4 × ( 15 - t ). \:\:\: (Total \: time \: taken \: = 15)}$

$\large\mathrm{⟹ x = 60}$_____(2)

$\large\underline\mathrm\red{Solving \: Eq \: (1) \: and \: (2). \: We \: get}$

$\large\mathrm{⟹ 8t = 60 \: - \: 4t}$

$\large\mathrm{⟹ 12t = 60}$

$\large\mathrm{⟹ t = 5}$

$\large\underline\mathrm\red{Thus}$,

$\large\underline\mathrm\red{Distance \: ⟹ \: speed \: × \: time}$

$\large\mathrm{Distance \: ⟹ 8 × 5}$

$\large\mathrm{Distance ⟹ 40 km.}$

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