Question

A boat of mass 200 kg is accelerated by an engine of power 16 kW. If the boat covers a distance of 72 km in 2 hours, the acceleration of the boat is 1. 8x10-2 m/s2 2.8x10-7 m/s2 3.8 m/s2 4. 80 m/s2​

Answer 1

option 3) 8 m/s²

Explanation:

\begin{gathered}power \: = \frac{force \: \times distance}{time} \\ 16 \times {10}^{3} = \frac{m \: \times a \: \times 72 \times 1000}{2 \times 60 \times 60} \\ \frac{16000 \times 2 \times 60 \times 60}{72 \times 1000} = 200 \times a \\ \frac{1600}{200} = a \\ a = 8 \frac{m}{ {s}^{2} } \end{gathered}

power=

time

force×distance

16×10

3

=

2×60×60

m×a×72×1000

72×1000

16000×2×60×60

=200×a

200

1600

=a

a=8

s

2

m

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answer by snehitha

Answer 2

Answer:

Acceleration of boat is 8 m/s^2

Explanation:

Concept: Power=Force . velocity

Then , Force = mass x acceleration

Given :

Mass of boat- 200 kg

Power of engine- 16kW=16000W

Distance cover by boat- 72km= 72000 m

Time taken to cover distance - 2hrs= 2x60x60= 7200 sec

Find: Acceleration of boat

Step by step explanation:

Power(P)= Force x velocity

Velocity= Distance/ Time taken

Velocity= 72000/7200= 10 m/s

So the velocity of boat is 10 m/s.

Force (f). = mass x acceleration

Force = 200kg x acceleration(a)

Then,

Power= Force x velocity

Power= mass x acceleration x velocity

Power= 200x a x 10

16000/2000= a

acceleration (a) = 8 m/s^2

No option is given

Acceleration of boat is 8 m/s^2

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