Question

A boat of mass 3000 kg,initially at rest is pulled by a force of 1.8×10⁴ N through a distance of 3m.Assuming the resistence of water due to water is
negligible,velocity of boat is

Answer 1

F = ma
1.8 × 10^4 = 3000 × a
a = (1.8 × 10^4) / 3000
a = 6 m/s^2

v^2 - u^2 = 2aS
a = (v^2 - u^2) / (2S)
6 = v^2 / (2 × 3)
v = 6 m/s

Velocity of boat is 6 m/s

Answer 2

Answer:

6m/s

Explanation :-

Given that,

u=0

force (f) =1.8×10⁴ N

distance [S] = 3m

velocity (v) =?

sol:-

we know that,

f=ma

•°• a =f/m

a = 1.8 ×10⁴/3000

a= 18 ×10³/3 ×10³

a= 18/3

•°• a= 6 m/s²

from the equation,

v² -u² =2as

v² = 2(6)(3)

v² = 12(3)

v² = 36

v =

${v} = \sqrt{36}$

$v = \sqrt{ {6}^{2} }$v = 6 m/s²