A boat of mass 40kg is at rest. A dog of mass 4 kg moves in the boat with velocity 10m/s what is the velocity of the boat(nearly)
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22
Answer:
Explanation:
=> It is given that,
Mass of boat, M₁ = 40 kg
Mass of Dog, M₂ = 4 kg
Velocity of dog, V₂ = 10 m/s
Velocity of boat, V₁= x
=> As per the law of conservation of linear momentum, momentum of boat is equal to the momentum of dog. Thus,
M₁V₁=M₂V₂
40 * V₁ = 4 * 10
V1 = 4 * 10 / 40
= 40 / 40
= 1 m/s
Thus, the velocity of the boat is 1 m/s.
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2
Answer is 0.6ms-1
60/6=10
10÷15= 0.66666.......
=0.6ms-1
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