A boat sails 12 km towards north and then 35 km towards east. Find the distance between the starting point and the the stopping point of the boat.
Answers
Answered by
32
Using phy thm.
35square+12sq.=
1225+144=
Root
1369
Distancr b/w staring point nd stopping point
root1369
35square+12sq.=
1225+144=
Root
1369
Distancr b/w staring point nd stopping point
root1369
Answered by
49
By pythagoras' Theorem,
in a right angled triangle,
(H*H)=(P*P)+(B*B)
Here,The distance between starting and stopping point of the boat will be H.
(H*H)=(12*12)+(35*35)
(H*H)=144+1225
(H*H)=1369
H=37
So,the distance between starting and stopping point is 37 km.
If this answer helped you,please mark as brainliest.
in a right angled triangle,
(H*H)=(P*P)+(B*B)
Here,The distance between starting and stopping point of the boat will be H.
(H*H)=(12*12)+(35*35)
(H*H)=144+1225
(H*H)=1369
H=37
So,the distance between starting and stopping point is 37 km.
If this answer helped you,please mark as brainliest.
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