Math, asked by singhsita73, 11 months ago

A boat sails 30 miles north and then 40 miles east. How far has the boat traveled, and what was its location from the start point.

Please provide details, I am self-teaching and a bit week at angles
Appreciate your help!

Answers

Answered by mysticd
3

Answer:

 \blue { Boat \: location \: is \: at \: C }

 \green { Distance \: travelled AC = 50 \: miles}

Step-by-step explanation:

A is the starting point a boat sails 30 miles towards North and then at point B it turned towards East sails 40 miles .

Finally it's located at point C.

AB = 30 miles

BC = 40 miles

 Distance \: travelled AC \\=\sqrt{ AB^{2} + BC^{2} }\\= \sqrt{ 30^{2} + 40^{2}}\\= \sqrt{900 + 1600}\\= \sqrt{ 2500}\\= \sqrt{50 \times 50}\\= 50 \:miles

Therefore.,

 \blue { Boat \: location \: is \: at \: C }

 \green { Distance \: travelled AC = 50 \: miles}

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