Question

A boat sails on a bearing of 038° and then 5km on a bearing of 067°. How far is the boat from its starting point and calculate the bearing of the boat from its starting point.

Answer 1

Step-by-step explanation:

simplest way is using vectors.

resultant vector

= (4cos38,4sin38) + (5cos67,5sin67)

= (3.152.., 2.4626..) + (1.9536..., 4.6025..)

= (5.1056.., 7.065...)

distance = √(5.1056..^2 + 7.065.^2)

= appr 8.717 correct to 3 decimals

bearing:

tanØ = 7.065../5.1056..

Ø = 54.146°