Question

A boat starts sailing on Monday 10:00 at harbour A and sails 600km due north.later it turns east for further 420km to reach harbour B on Tuesday at 12:00.

What is the Total displacement from A to B Average is there a formula i need to follow​

Answer 1

a. displacement = sqrt(600^2+420^2)

b. distance = 600+420 = 1020

so speed = 1020/time

c.average velocity = answer from part a / time

but velocity also has a direction since it is a vector

tan angle east of north = 420/600

Answer 2

Answer:

I have attached the answer