A boat takes 60 minutes less to travel 40 km downstream than to travel the same distance upstream. if the speed of the boat in still water is 15 kmph. what is the speed of the stream
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Answered by
24
Let the speed of Stream be y km/h then
Let the time taken to go 40 km downstream be t hours
then the time taken to go 40 km upstream is (t+1) hours .........since 60 min=1 hr
Also,
time = distance/ speed
so,
t=40/(15+y)
t+1=40/(15-y)
Now,
=>40/(15-y) - 40/(15+y) = 1
=> y²+80y - 225 =0;
we get,
y= 2.72 km/h
so the speed of the stream is 2.72 km/h
Let the time taken to go 40 km downstream be t hours
then the time taken to go 40 km upstream is (t+1) hours .........since 60 min=1 hr
Also,
time = distance/ speed
so,
t=40/(15+y)
t+1=40/(15-y)
Now,
=>40/(15-y) - 40/(15+y) = 1
=> y²+80y - 225 =0;
we get,
y= 2.72 km/h
so the speed of the stream is 2.72 km/h
Answered by
7
Given :
Let the speed of the stream be X km/h thenSpeed downstream =(15+x) km/hSpped upsstream =(15-x )km/h
40/(15-x) - 40/(15+x)=60/60
40(15+x)-40(15-x)=(15-x)²
600 +40x -600+40x= 225-x²
x² +80x -225=0
Solving the above quadratic equations we get :
X=( - b± √b²-4ac)/2a
here a=1
b= -80
c=225
b²-4ac= 6400-900 =5500
x=80± √5500/2
on solving for X we get,
X=2.919
Therefore speed of stream =2.919 km/hr
Let the speed of the stream be X km/h thenSpeed downstream =(15+x) km/hSpped upsstream =(15-x )km/h
40/(15-x) - 40/(15+x)=60/60
40(15+x)-40(15-x)=(15-x)²
600 +40x -600+40x= 225-x²
x² +80x -225=0
Solving the above quadratic equations we get :
X=( - b± √b²-4ac)/2a
here a=1
b= -80
c=225
b²-4ac= 6400-900 =5500
x=80± √5500/2
on solving for X we get,
X=2.919
Therefore speed of stream =2.919 km/hr
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