Question

A boat takes off from the dock at 2.5 m/s and speeds up at 4.2 m/s2 for 6.0 s. How far has the boat traveled? Round your answer to the nearest whole number.

Answer 1

Since, distance in velocity time graph is equal to the area of figure formed......its for grade 11......hope it helped....mark as brainliest

Answer 2

The distance traveled by the boat is 91 m (nearest whole number)

Given:

Initial velocity, u = 2.5 m/s

Acceleration, a = 4.2 $m/s^2$

Time, t = 6 s

Solution:

We calculated this using one of the equations of motion. The three equations of motion are mentioned below.

1. $v=u+a t$
2. $s=u t+\left(\frac{1}{2}\right) a t^{2}$
3. $v^{2}=u^{2}+2 a s$

We can use any of these equations depending upon the requirements of the question and as per the information provided in the question.

In this question, we need to use the below given equation of motion,

$\Rightarrow s=u t+\frac{1}{2} a t^{2}$

$\Rightarrow s=(2.5 \times 6)+\left(\frac{1}{2} \times 4.2 \times 6^{2}\right)$

$\Rightarrow s=(15)+75.6$

$\therefore s=90.6 m \approx 91 m$