A boat travels 8 km/hr in still water. If the velocity of water current is 4 km/hr, at what angle of the shore the boat be stretched to reach the boat in opposite point?
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⇒ Let x be the speed of the stream.
⇒ Speed of the boat in still water is 8km/hr
⇒
The speed of the boat in upstream is
8−
xkm/hr
⇒
The speed of the boat in downstream is
8+
xkm/hr
⇒
The time taken by the boat to cover
15km=
8−x
15
hr
⇒
The time taken by the boat to cover
22km=
8+x
22
hr
According to the question,
⇒
8−x
15
+
8+x
22
=
5
⇒
15(8+
x)+
22(8−
x)=
5(8−
x)(8+
x)
⇒
120+
15x+
176−
22x=
5(64−
x 2
⇒
296−
7x=
320−
5x
2
⇒
5x
2
−
7x−
24=
0
⇒
5x
2
−
15x+
8x−
24=
0
⇒
5x(x−
3)+
8(x−
3)=
0
⇒
(x−
3)(5x+
8)=
0
⇒
x−
3=
0
and
5x+
8=
0
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