A boat travels from south bank to north bank of a river with a maximum speed of "8km/h" .A river current flows from west to east with a speed of "4km/h" .Find the angle with which the boat should be steered to arrive at a point opposite to the pointof
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Answer:
30° Towards West from North
Explanation:
Let say Boat moved with an angle α with East toward North with speed of 8 km /hr
Then Velocity toward East (west to East) = 8 Cosα
.A river current flows from west to east with a speed of 4km/h
Addition of both speed should be zero so that Boat moves only
with 8Sinα in North Direction (South to North)
8Cosα + 4 = 0
=> Cosα = - 4/8
=> Cosα = -1/2
=> α = 120 °
120° towards North from East
or 30° Towards West from North
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