Question

A Bob executes SHM of period 20sec it's velocity is 5cm per second, 2sec after it has passed the mean position find amplitude of the Bob​

Answer 1

Answer:

Dear student,

Given:

Time period, T = 20 s

Velocity of bob, v = 5 cm/s

Time, t = 2 s

The displacement of the pendulum can be given as:

y=Acosωt

This implies that the velocity of the bob will be

v=dydt=−ωAsinωt⇒v=−2πTAsin(2πTt) (∵ω=2πT)⇒5=2π20×A×sin(2π20×2)=π10×A×sin(π5)=0.18A⇒A=50.18=27.78 cm

This is the required amplitude.

Regards

Explanation:

hope it helps you