Question

A Bob of mass 0.1 kg hung from the ceiling of a room by a string 2 m long is set into oscillation. The speed of the Bob at its mean position is 1 m s⁻¹. What is the trajectory of the bob, if the string is cut when the bob is a. at one of its extreme positionsb. at its mean position

Answer 1

Hii friend,

● Answers-
a) straight downward
b) parabolic

● Explanation-
a) If the string is cut when particle is at extreme position-
At this instant
velocity = 0
Thus, bob will fall straight downward due to gravity.

b) If the string is cut when particle is at mean position-
At this instant
velocity = 1 m/s tangential to oscillating path.
Thus, particle will move along parabolic trajectory like a projectile.

Hope, this is useful...

Answer 2

☺Hello frds_____

✒Your answer is here ⤵

(a) Vertically downward, Parabolic path

▶▶▶ At the extreme position, the velocity of the bob becomes zero. If the string is cut at this moment, then the bob will fall vertically on the ground.

(b) At the mean position, the velocity of the bob is 1 m/s. The direction of this velocity is tangential to the arc formed by the oscillating bob. If the bob is cut at the mean position, then it will trace a projectile path having the horizontal component of velocity only.

▶▶Hence, it will follow a parabolic path.

I hope, this will help you

Thank you____❤

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