Question

A bob of mass M is suspended by a massless string of length
L. The horizontal velocity v at position A is just sufficient to
make it reach the point B. The angle at which the speed of
the bob is half of that at A, statisfies
(2008, 3M)
A v
T
TT
(b) - <O<
(a) 0 =
b)<
e<
2
4
<<T
(c)
3T
(d)
4
T
Зл
<<
4
2​

Answer 1

explanation:

21 M( 5gl ) 2 = 21 M( 25gl ) 2 +Mgl(1−cosθ)

21 M 43×5gl = Mgl(1−cosθ)

1−cosθ= 815

cosθ=1− 815

cosθ=1−815

cosθ=−87

θ=1520

43π<θ<π

MARK ME AS BRILLIANT