Physics, asked by pranjul4742, 1 year ago

A bobcat jumps with a speed of 5 m/s at an angle of 55°. How long does the bobcat stay in the air?

Answers

Answered by bharti7267
0

T=(2usin@)÷g

=(2×5×sin55°)÷10

=sin55°

=0.8191 seconds

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