Question

A bobsled team accelerates the sled to go to 150 m/s in 3 seconds from rest.
(a)What is the sled’s acceleration?
(b) What is the distance the bobsled team traveled?

Answer 1

Answer:

After 1 second, the velocity is 4.5+1.5=6 m/s. After 3 seconds, the velocity is 4.5+3×1.5=9 m/s.

Explanation:

Answer 2

(a) 50 $ms^{-2}$ , (b) s =  225 m

Given:

Initial velocity(u) = 0

Final velocity(v) =  150$ms^{-1}$

Time (t)= 3 sec.

To find : (a) Sled's acceleration(a)

v-u=at

a= $\frac{v-u}{t}$

a = $\frac{150-0}{3}$

a= 50 $ms^{-2}$

Therefore, Sled's acceleration is  50 $ms^{-2}$

To find : (b) The distance(s) the bobsled team traveled.

We have ,

s = ut + $\frac{1}{2}at^{2}$ (Where s is the distance travelled )

s = 0 + $\frac{1}{2}(50)(3^{2})$

s =  225 m

Therefore, the distance travelled by the bobsled team is 225 m.

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