Question

A bod is moving with constant retardation in straight line 5.7 m and 3.9 m in 6th and 9th sec. respectively. when will the body come momentarilly to rest

Answer 1

firstly , difference between distance= 5.7-3.9= 1.8 m , difference between time = 9th-6th=3 so it means every 3 sec 1.8 distance decrease . in (9+3)s=12s distance will 3.9-1.8= 2.1 m . and in (12+3)s the distance will 2.1- 1.8= 0.3 . if in 3s 1.8 distance is covered , then in 1 s distance covered =1.8/3= 0.6m . and in 0.3m time will be 0.3 sec . so required time = 15 +0.3 s= 15.3 sec ans. THANKYOU