Question

a body A is N times heavier than body B.They are dropped from the same height.
What is the ratio of their momentum just before they hit the ground? ​

Answer 1

Explanation:

Mass of body B = m

Mass of body A = nm

Height from which they are dropped = h

their velocity just before hitting ground = √2gh

momentum of A = nm√2gh

momentum of B = m√2gh

Ratio = \frac{nm \sqrt{2gh} }{m \sqrt{2gh} } = nm2ghnm2gh=n