Physics, asked by kaushikabhi, 1 year ago

A body A is n times heavier than body B. They are dropped from the same height. What is theratio of their moment just before they hit the ground?

Answers

Answered by rupemon
4
If there is no air resistance, then both the bodies will hit the round at the same time. 
Ratio= 1:1
But in the presence of air resistance, A hits the ground faster
ratio= n:1


Answered by TPS
9
Mass of body B = m
Mass of body A = nm
Height from which they are dropped = h
their velocity just before hitting ground = √2gh

momentum of A = nm√2gh
momentum of B = m√2gh

Ratio =  \frac{nm \sqrt{2gh} }{m \sqrt{2gh} } = n

TPS: Thank you Kaushik!!
kaushikabhi: ur wlcm :)
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