A body A is n times heavier than body B. They are dropped from the same height. What is theratio of their moment just before they hit the ground?
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Answered by
4
If there is no air resistance, then both the bodies will hit the round at the same time.
Ratio= 1:1
But in the presence of air resistance, A hits the ground faster
ratio= n:1
Ratio= 1:1
But in the presence of air resistance, A hits the ground faster
ratio= n:1
Answered by
9
Mass of body B = m
Mass of body A = nm
Height from which they are dropped = h
their velocity just before hitting ground = √2gh
momentum of A = nm√2gh
momentum of B = m√2gh
Ratio =
Mass of body A = nm
Height from which they are dropped = h
their velocity just before hitting ground = √2gh
momentum of A = nm√2gh
momentum of B = m√2gh
Ratio =
TPS:
Thank you Kaushik!!
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