Question

A body A is resting on a rough surface of u = 0.6, then the static frictional force is
A
2Kg
77
a) 12 N
b) 6N
c) zero
d) 24 N​

Answer 1

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Answer 2

12N

Explanation:

Mass of body = 12kg

Coefficient of static friction (μ$)_{s}$ = 0.6

Gravitational constant (g) = 10 (take 10 unless specified as 9.8)

Formula for static frictional force = μmg

                                     = (0.6) * 12 * 10

All units are in their standard form so there is no need for conversion of values

                                     = 1.2 * 10

                                     = 12N

∴ static frictional force is 12N