Physics, asked by sjeevanswaroop007, 8 months ago

A body A of mass m is moving in a circular orbit of radius R about a planet. Body A collides with another body B of
mass m-2 moving with a velocity which is half the instantaneous velocity of A. The collision is completely inelastic.
Then, the combined body:​

Answers

Answered by shraeyparashar0506
0

Answer:V=m1v+2m2v/m1+m2

Explanation: V=velocity of the bodies after the collision.

v1=velocity of the body A

v2 = velocity of body B

NOW, by the formula of the inelastic collision,

=m1v1+m2v2=m1V+m2V

V= m1v1+m2v2/m1+m2  

V=m1v1+2m2v1/m1+m2 (as given, v2=1/2v1)

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