Question

a body A starts from restwith an acceleration a1. after 2 seconds another body B starts from rest with an acceleration a2. if they travel equal distances in the 5th second then the ratio a1:a2 equal is

Answer 1

The ratio of a1 : a2 is 5 : 9

Explanation:

Body A:

Acceleration = a1

Time = t

$s=u t+\frac{1}{2} a 1 . t^{2}$

$s=\frac{1}{2} a 1 . t^{2}$

Since, we need to find distance travelled in 5th second, we need find the difference between the distance travelled in 5 seconds and the distance travelled in 4 seconds.

Distance travelled in 5th second:

$s=\frac{1}{2} a 1 .(5)^{2}-\frac{1}{2} a 1 .(4)^{2}$

$s=4.5(a 1)$

Body B:

Acceleration = a2

Time = t – 2

$s=u t+\frac{1}{2} a 2 \cdot(t-2)^{2}$

$s=\frac{1}{2} a 2 .(t-2)^{2}$

Distance travelled in 5th second:

$s=\frac{1}{2} a 2 .(5-2)^{2}-\frac{1}{2} a 2 \cdot(4-2)^{2}$

$s=\frac{9}{2} a 2-\frac{4}{2} a 2$

$s=\frac{5}{2}(a 2)$

$s=2.5(a 2)$

The distance are equal,

$4.5(a 1)=2.5(a 2)$

$\frac{a 1}{a 2}=\frac{2.5}{4.5}$

$\Rightarrow \frac{a 1}{a 2}=\frac{5}{9}$

The ratio of a1 : a2 is 5 : 9

Answer 2

Answer:ariyila monuse

Explanation: onum illa

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