Physics, asked by alfrisophana70, 10 months ago

A body accelarates uniformly from 10m/s to 25m/s in 5 sec. Find:
a) The velocity of the body the next five second
b) The distance covered by the body in that time.

Plss answer this fast. I request you to give the answer clearly. If the answer is correct you will be marked the brainliest.

Answers

Answered by savitawadhwa
1

Answer:

see below

Explanation:

a) v=u+at

acceleration = (v-u)t

so , acceleration = (25m - 10m)/5

a = 3ms raise to power -2

v = 10m + 3ms × 5s

v = 25m

b) s = ut + a×t×t

s=10m×5s+3m×5s×5s

s=125m

Answered by negisakshi1978
1

Explanation:

first find the accleration by using formula

a=v-u/t then,

In a) by using 1st equation of motion

v=u+at you can find velocity ,put the value of accleration in a.

b)by using 3rd equation of motion you can find distance

S=ut+1/2 atsquare

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