A body accelarates uniformly from 10m/s to 25m/s in 5 sec. Find:
a) The velocity of the body the next five second
b) The distance covered by the body in that time.
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Answers
Answered by
1
Answer:
see below
Explanation:
a) v=u+at
acceleration = (v-u)t
so , acceleration = (25m - 10m)/5
a = 3ms raise to power -2
v = 10m + 3ms × 5s
v = 25m
b) s = ut + a×t×t
s=10m×5s+3m×5s×5s
s=125m
Answered by
1
Explanation:
first find the accleration by using formula
a=v-u/t then,
In a) by using 1st equation of motion
v=u+at you can find velocity ,put the value of accleration in a.
b)by using 3rd equation of motion you can find distance
S=ut+1/2 atsquare
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