A body accelerate uniformly from rest at the rate of 3m/s2 for 8s calculate the distance covered by the body during acceleration
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Answered by
33
hey
______
u (initial velocity) = 0
a (acceleration) = 3m / s^2
t(time) = 8s
s (distance) = ?
refer to the attachment for the ans
hope helped
____________
______
u (initial velocity) = 0
a (acceleration) = 3m / s^2
t(time) = 8s
s (distance) = ?
refer to the attachment for the ans
hope helped
____________
Attachments:
Anonymous:
correct sis!
Answered by
33
Here, In this question
u = 0 ( body starts from rest)
a = 3m/^2
t = 8 s
Now,
In order to find distance, We will apply Second equation of Motion :-
S = ut + 1/2 at^2
=> S = 0 + 1/2 x 3 x 8 x 8
=> S =( 3 x 4 x 8) m
=> S = 96 m
Be Brainly
u = 0 ( body starts from rest)
a = 3m/^2
t = 8 s
Now,
In order to find distance, We will apply Second equation of Motion :-
S = ut + 1/2 at^2
=> S = 0 + 1/2 x 3 x 8 x 8
=> S =( 3 x 4 x 8) m
=> S = 96 m
Be Brainly
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