A body accelerate uniformly from rest of 2m/s square . Calculate it's velocity after traveling 9m
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Answer:
6 m/s
Explanation:
Given :
- A body accelerates uniformly from rest at 2 m/s²
To find :
- the velocity of the body after travelling 9 m
Solution :
- Since the body accelerated from rest
⇒ initial velocity, u = 0 m/s
- The body accelerated at 2 m/s²
⇒ acceleration, a = 2 m/s²
- Distance travelled, s = 9 m
- Final velocity, v = ?
From the third equation of motion,
v² = u² + 2as
where
v - velocity after travelling "s" distance
u - initial velocity
a - acceleration
s - distance covered
Substituting the values,
⤳ v² = 0² + 2(2)(9)
⤳ v² = 0 + 36
⤳ v² = 36
⤳ v = √36
⤳ v = 6 m/s
Therefore, the velocity of the body after travelling 9 m = 6 m/s
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