Question

A body accelerate uniformly from rest of 2m/s square . Calculate it's velocity after traveling 9m

Answer 1

Answer:

6 m/s

Explanation:

Given :

• A body accelerates uniformly from rest at 2 m/s²

To find :

• the velocity of the body after travelling 9 m

Solution :

• Since the body accelerated from rest

       ⇒ initial velocity, u = 0 m/s

• The body accelerated at 2 m/s²

       ⇒ acceleration, a = 2 m/s²

• Distance travelled, s = 9 m

• Final velocity, v = ?

From the third equation of motion,

v² = u² + 2as

where

v - velocity after travelling "s" distance

u - initial velocity

a - acceleration

s - distance covered

Substituting the values,

⤳ v² = 0² + 2(2)(9)

⤳ v² = 0 + 36

⤳ v² = 36

⤳ v = √36

⤳ v = 6 m/s

Therefore, the velocity of the body after travelling 9 m = 6 m/s